UNIVERSITY PARK, Pa.; February 5, 2019 – Penn State Nittany Lion Bo Nickal (Allen, Texas) has been named the Big Ten Wrestler of the Week for the week ending February 10, 2019. Nickal earns Penn State's fourth weekly honor of the 2018-19 season and his second of the year.
Nickal continued his national dominance by handing No. 2 Kollin Moore of Ohio State his first loss of the season on Moore's home mat. Nickal locked up a textbook cradle midway through the opening period of their marquee match-up in Columbus on Friday night and pinned the second-ranked Buckeye at the 1:38 mark.
The pin was one of many highlights in Penn State's 28-9 win over No. 2 Ohio State in the nationally televised dual in sold out St. John Arena. Penn State won seven of ten bouts in the dual meet to remain unbeaten on the year, improving to 11-0, 7-0 in the conference. Nickal's pin was his 13th of the year and the 54th of his career. He is second all-time in pins at Penn State, trailing teammate Jason Nolf who has 56. Nickal is 19-0 on the year and 109-3 for his career. 85 of his 109 wins are for bonus.
Penn State will host Michigan State on Friday, Feb. 15, at 7 p.m. in sold out Rec Hall and then visit Illinois on Sunday, Feb. 17, for a 2 p.m. (Eastern) dual meet.
Penn State Fans are encouraged to follow Penn State wrestling via twitter at @pennstateWREST, on Penn State Wrestling's Facebook page at www.facebook.com/pennstatewrestling and on Instagram at www.instagram.com/pennstatewrest. This is PENN STATE. WRESTLING lives here.
